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Math / Sample Size

Sample Size Calculator

Estimate a survey sample size for a population proportion using a confidence level, margin of error, expected proportion, and optional finite-population correction. The result is rounded up because a partial respondent cannot satisfy the requested precision. The large-population estimate is n₀=z²p(1−p)/e². For finite population N, apply n=n₀/[1+(n₀−1)/N]. The method assumes a simple random sample and a proportion outcome.

Your inputs

Make it your own
Calculator settings
%

%

%

people

Your result
385
responses
Required sample size
Result breakdownUncorrected estimate: 384.15Required whole responses: 385
responsesUncorrected estimate · 384.15Required whole responses · 385
Unrounded estimate
384.15
z critical value
1.96

Example inputs shown. Adjust them to explore.

A familiar situation

Plan the approximate response count for a poll based on confidence and margin-of-error targets.

How to use this calculator

  1. Enter confidence level, margin of error, expected proportion and the remaining inputs.
  2. Select Calculate to see the answer and its breakdown.
  3. Keep a scenario, change an input and compare the results.

Use consistent units and check the assumptions below before applying the result.

How sample size is calculated

The large-population estimate is n₀=z²p(1−p)/e². For finite population N, apply n=n₀/[1+(n₀−1)/N]. The method assumes a simple random sample and a proportion outcome. At 95% confidence, 5% margin, and p=0.5, a large population needs about 385 responses.

n₀=z²p(1−p)/e²; finite population n=n₀/[1+(n₀−1)/N].
A worked example

At 95% confidence, 5% margin, and p=0.5, a large population needs about 385 responses.

Assumptions & useful context

The result depends on the values you enter and the method described above. Displayed numbers may be rounded; calculations use the unrounded values. Check that this model matches your situation before relying on it.

Frequently asked questions

Why is 50% the default proportion?

It maximizes p(1−p), producing a conservative largest sample estimate when the true share is unknown.

Does this guarantee a representative sample?

No; nonresponse and sampling design can introduce bias that the formula does not remove.

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